The equations 9 x minus 10 y = 6, 8 x minus 10 y = negative 23, 9 x + 10 y = negative 16, and 8 x + 10 y = 13 are shown on the graph below. On a coordinate plane, there are 4 lines. Green line goes through (negative 2, 0.75) and (negative 2, 1.5). Blue line goes through (negative 1.75, 0) and (1, negative 2). Pink line goes through (negative 1.5, negative 2), and (1.5, 0.75). Purple line goes through (0, 1.25) and (1, 0.5). Which is the approximate solution for the system of equations 8 x minus 10 y = negative 23 and 9 x + 10 y = negative 16?

i would go with the first one

step-by-step explanation:

hope this

if x decreases by 4 then y increases by 10

step-by-step explanation:

more detail

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.