Two airplanes leave the airport. Plane A departs at a 41° angle from the runway, and plane B departs at a 43° from the runway. Which plane was farther away from the airport when it was 5 miles from the ground? Round the solutions to the nearest hundredth. Plane A because it was 7.62 miles away Plane A because it was 6.63 miles away Plane B because it was 6.84 miles away Plane B because it was 7.33 miles away

Plane A because it was 7.62 miles away.

Step-by-step explanation:

In the case of plane A we have a right triangle with an angle of 41 degrees and the opposite side  = 5.

The distance of the planes from the airport is the hypotenuse of the triangles.

sin 41 = opposite / hypotenuse

sin 41 = 5 / h       where h is the distance of the plane from the airport so

y = 5 / sin 41 = 7.62 miles.

By a similar process for Plane B  we see that sin 43 = 5/h

h = 5 / sin 43 = 7.33 miles.

the correct answer is a) they believe they have a "just cause."

islamic terrorists justify their violent actions because they believe they have a "just cause."

every act of terrorism of islamic sects is done “in the name of allah”. that justifies their actions. islam people who commit those terrorist attacks are not afraid to die. that is why the attacks have horrible consequences. they know they are going to die and they are proud to do it because it is in the name of allah, so it is justified and is for a “good cause.”

since the very beginning of the conflict with israel, islam is fighting a “sacred war”, respecting the words stated in the qur’an. they fight against the domination of the western countries and to defend their occupied territories.

i cant answer this, theres no table. sorry man

step-by-step explanation: