1. Compute (5+3i)(5-3i) express your answer in the form of a+bi, where a and b are real numbers.

2. Express (2+i)/(4+i) in the form of a+bi, where a and b are real numbers.

3. Find all complex number z satisfying the equation (z+1)/(z-1)=i

THANKS SO MUCH FOR YOUR HELP!!!

1) 34 + 0i

2) 9/17 + (2/12)i

3) z = -i

Step-by-step explanation:

(5 + 3i)(5 - 3i) = 25 - 15i + 15i - 9i²

25 - 15i + 15i - 9i² = 25 - 9i²

25 - 9i² = 25 - 9√(-1)²

25 - 9√(-1)² = 25 - 9(-1)

25 - 9(-1) = 25 + 9

25 + 9 = 34

34 = 34 + 0i

(2 + i) / (4 + i)

a=2, b= 1 , c=4 , d =1

Solve like part 2:

z = -i

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )