Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73' Building A is 30 feet away, and building Bis 35 feet away. Which building is taller and by approximately how many feet?

Building A, it is around 16 35 feet taller than building B

Building At is around 114 48 feet taller than building B

Building B, it is around 16 35 feet taller than building A

Building B, it is around 114 48 feet taller than building A

(C)Building B, It is around 16.35 feet taller than building A.

Step-by-step explanation:

In the diagram, the distance from Kayson(K) to Building A is 30 feet while the distance from Kayson(K) to Building B is 35 feet.

(a)Building B is taller

(b)

In Right Triangle KAL

In Right Triangle KMB

Difference in Height = 114.48 - 98.13

=16.35 feet

Therefore, Building B is taller by approximately 16.35 feet.

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)