Mathematics, 26.06.2020 20:01 silasjob09

We wish to estimate what percent of adult residents in a certain county are parents. Out of 400 adult residents sampled, 296 had kids. Based on this, construct a 95% confidence interval for the proportion p of adult residents who are parents in this county. Express your answer in tri-inequality form. Give your answers as decimals, to three places. < p < Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.
p = ±±
2.
Giving a test to a group of students, the grades and gender are summarized below
A B C Total
Male 14 8 15 37
Female 13 18 12 43
Total 27 26 27 80
Let p represent the population proportion of all female students who received a grade of C on this test. Use a 95% confidence interval to estimate p to four decimal places if possible.
_< p <
3. Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 308 with 136 successes. Enter your answer as an open-interval (i. e., parentheses) using decimals (not percents) accurate to three decimal places.
C. I. =
4. Assume that a sample is used to estimate a population proportion p. Find the 90% confidence interval for a sample of size 276 with 36% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.
< p <_

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We wish to estimate what percent of adult residents in a certain county are parents. Out of 400 adul...

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