In a coffee shop "Scratch and Win" contest, one out of three cards is a winner. What is the probability that Shenice would first win on her third try? a.4/9

b. 1/27

c.4/27

d. 8/81

C.) 4/27

Step-by-step explanation:

Given that:

One out of three cards is a winner :

P(winning) = 1 / 3

Therefore, P(not winning) = P(losing) :

1 - P(winning) = 1 - 1/3 = 2/3

Probability that shenice will first win on her third try can be interpreted as:

1st try = lose, 2nd try: lose, 3rd try : win

P(losing) × p(losing) × p(winning)

(2/3) × (2/3) × (1/3)

4 / 27

Probability of first winning on third try = 4/27

4.6875 pounds

step-by-step explanation:

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72