the lengths of the rectangle have been measured to the nearest tenth of a metre work out the following, writing down all the figures on your calculator display: a) The upper bound for the perimeter of the rectangle. b)The lower bound for the area of the rectangle. rectangle lengths = 15.8m width = 5.2m

Perimeter = 42.2 m

              Area = 81.1125 m²

Step-by-step explanation:

                                                      Lower     Upper

Length is given as 15.8    -->         15.75 ≤ L < 15.85

width is given as 5.2       -->           5.15 ≤ w < 5.25

Perimeter = 2L + 2w     (Upper bound)

                = 2(15.85) + 2(5.25)

                =   31.7      +   10.5

                =   42.2

Area = Length x width     (Lower bound)

        = 15.75 x 5.15

        = 81.1125

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.