29.22 The point-slope form of the equation of the line that passes through (-5, -1) and (10,-7) is
Y+7=
-- (x - 10). What is the
standard form of the equation for this line?
O 2x - 5y = -15
2x - 5y = -17
O 2x + 5y = -15
2x + 5y = -17

2x +5y = -15

Step-by-step explanation:

We need to find the slope

m = (y2-y1)/(x2-x1)

   = (-7--1)/(10- -5)

   = (-7+1)/(10+5)

   -6/15

  -2/5

The point slope form

Y+7= -2/5 (x - 10).

Distribute

y + 7 = -2/5x + 4

Add 2/5 x to each side

2/5x +y +7 = 4

Subtract 7 from each side

2/5x +y = -3

Multiply each side by 5

5(2/5x +y) = -3*5

2x +5y = -15

This is standard form Ax + By = C where A is a positive integer

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point