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Mathematics, 26.06.2020 16:01 Kianna000
Part of a cross-country skier's path can be described with the vector function r = <2 + 6t + 2 cos(t), (15 ā t)(1 ā sin(t))> for 0 ā¤ t ā¤ 15 minutes, with x and y measured in meters. The derivatives of these functions are given by xā²(t) = 6 ā 2sin(t) and yā²(t) = ā15cos(t) + tcos(t) ā 1 + sin(t).1. Find the slope of the path at time t = 4. Show the computations that lead to your answer.2. Find the time when the skier's horizontal position is x = 60.3. Find the acceleration vector of the skier when the skier's horizontal position is x = 60.4. Find the speed of the skier when he is at his maximum height and find his speed in meters/min.5. Find the total distance in meters that the skier travels from t = 0 to t = 15 minutes.
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Part of a cross-country skier's path can be described with the vector function r = <2 + 6t + 2 co...
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