Bob has to interview 4 different candidates. He has to schedule each of them at different times throughout the day. How many different ways can he schedule the candidates?

 24

Label the time slots as A,B,C,D

For time slot A, he has 4 candidates to pick from. Then for time slot B he has 3 choices left (he doesn't want to interview the same person again), and C has 2 choices, with D having just one choice. Effectively we start at 4 and count our way down to 1. We will multiply these values out.

Overall, Bob has 4*3*2*1 = 24 different ways to arrange the candidate interviews. This is known as a permutation because order matters.

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.