Probability: Deceit Someone please help me. My online statistics class isn't able to give me the help i need to confidently perform this problem.

85% of those trained were able to pass the polygraph examination even when guilty of a crime. suppose that a random sample of 9 students are told a "secret" and then given instructions on how to pass the polygraph examination without revealing the secret. what is the probability that: a) all the students are able to pass the polygraph examination? b) more than half the students are able to pass the polygraph examination? c) no more than four of the students are able to pass the polygraph examination? d) all the students fail the polygraph examination?

I put it into the calculator with binompdf. My n=9, probability of success=.85. For part (a) i got .23162. Am I doing this right?

Which is the standard form for this number? (4 x 1 100 ) + (8 x 1 1,000 ) + ( 3 x 1 100,000 ) ? a) 0.004803 b) 0.04803 c) 0.0483 d) 0.483

Tessa bought stock in a restaurant for $253.00. her stock is now worth $333.96. what is the percentage increase of the value of tessa's stock? a.) 81% b.) 32% c.) 24% d.) 76%

In a test for esp (extrasensory perception), the experimenter looks at cards that are hidden from the subject. each card contains either a star, a circle, a wave, a cross or a square.(five shapes) as the experimenter looks at each of 20 cards in turn, the subject names the shape on the card. when the esp study described above discovers a subject whose performance appears to be better than guessing, the study continues at greater length. the experimenter looks at many cards bearing one of five shapes (star, square, circle, wave, and cross) in an order determined by random numbers. the subject cannot see the experimenter as he looks at each card in turn, in order to avoid any possible nonverbal clues. the answers of a subject who does not have esp should be independent observations, each with probability 1/5 of success. we record 1000 attempts. which of the following assumptions must be met in order to solve this problem? it's reasonable to assume normality 0.8(1000), 0.2(1000)%30 approximately normal 0.8(1000), 0.2(1000)% 10 approximately normal srs it is reasonable to assume the total number of cards is over 10,000 it is reasonable to assume the total number of cards is over 1000