Answers: 2
![\dfrac{1}{216}^{-2/3}+\dfrac{1}{256}^{-3/4}+\dfrac{1}{243}^{-1/5}= \\\\\\\sqrt[3]{216^2}+\sqrt[4]{256^3}+\sqrt[5]{243}=\\\\\\6^2+4^3+3=\\\\\\36+64+3=\\\\\\103](/tpl/images/0694/3839/21a41.png)
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1/216^-2/3 + 1/256^-3/4 + 1/243^-1/5...
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