If 2x-3y=10. and xy=16 find the value of8x³-27y³

8x³-27y³=3880

Step-by-step explanation:

2x-3y=10

xy=16

8x³-27y³=?

as we know that

(a-b)³=a³-b³-3ab(a-b)

now we substitue the formula according to our question

(2x-3y)³=(2x)³-(3y)³-3(2x)(3y)(2x-3y)

(10)³=8x³-27y³-18(16)(10)

1000=8x³-27y³-2880

1000+2880=8x³-27y³

3880=8x³-27y³

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

okay wait before i answer, is this for your points on a graph?