What is the product of (5 m Superscript negative 2 Baseline) (2 m Superscript negative 3 Baseline)? StartFraction 7 Over m Superscript 5 EndFraction

7m6

StartFraction 10 Over m Superscript 5 EndFraction

10m6

C ) 10/m⁵

Step-by-step explanation:

In this question, we have to find the product of two terms

First term = 5 m⁻²

Second term = 2 m⁻³

Product of both terms = (5 m⁻²) · (2 m⁻³)

The simple way of calculating product of these two term which involves constants as well as variable is that we multiply the constants together:

5·2 = 10

And we multiply the variables. According to the rules of multiplication, when 2 same constants or variables are multiplied, we can just add their powers to get the result.

(m⁻²) · (m⁻³) = m⁻²⁻³ = m⁻⁵

The product of both terms can be written as:

(product of constants)(product of variables) = (10)(m⁻⁵) = 10/m⁵

So the correct option is C