Bronson is ordering pizza at a restaurant, and the server tells him that he can have up to three toppings: spinach, bacon, and pepperoni. Since he cannot decide how many of the toppings he wants, he tells the server to surprise him. If the server randomly chooses which toppings to add, what is the probability that Bronson gets just spinach? Express your answer as a fraction or a decimal number rounded to four decimal places.

The probability that Bronson gets just spinach is;

P = 1/7

or

P = 0.1429

Step-by-step explanation:

There are three possibilities;

- just one topping

- two topping

- three topping

For just one topping, the number of possible outcomes is;

N1 = 3C1 = 3!/(1!2!) = 3 possible outcomes

For two topping, the number of possible outcomes is;

N2 = 3C2 = 3!/(2!1!) = 3 possible outcomes

For three topping, the number of possible outcomes is;

N3 = 3C3 = 3!/3! = 1 possible outcomes

Total number of possible outcomes;

N = N1+N2+N3

N = 3+3+1 = 7

The probability that Bronson gets just spinach is;

Getting spinach is one out of seven possible outcomes, so;

P = 1/N = 1/7

P = 1/7 or 0.1429

4444444444444 i think

what is the rest of the question? ?