Please help will brainlest

1) 8zs² × 4z³s^5

= 32z⁴s^7

2) 5w^5 × 4w⁴

= 20w^9

3) 3r × 5r^5

= 15r^6

4) cz × 9c^5z²

= 9c^6z³

5) (1/r)⁴ × (1/r)^7 × (1/r)^6

= r^-4 × r ^ -7 × r^ -6

= r^ -17

6) 4h^6 × 2h³c²

= 8h^9c²

Hope this helps.

idk sry

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180