What is the point-slope form of a line with slope -3 that contains the point (10,-1)? A. y + 1 = 3(x+10)
B. y + 1 = 3(x-10)
C. y + 1 =-3(x-10)
D. x + 1 = -3(y -10)

the point slope form is

y + 1= -3(x - 10)

solution is c

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

days of the week

step-by-step explanation:

javier earned more money then kyle, so that won't always be a constant term, but the days of the week do not change so that term is always constant.

edit: i meant