Is the function even, odd or neither? f(x) = |x| + 1

Your

Even

Odd

Neither

Even

Step-by-step explanation:

This graph has been translated up by one unit but is still symmetrical about the y axis.

A simple proof would be to check if  f(x) = f(-x). If it does, then it is even.

To check for an odd function, check if f(-x) = -f(x). If it does, then it is even.

To check for neither, f(-x) will not equal -f(x)

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.