The equation x2 − 9 = 0 has real solution(s).

The roots are real and unequal (3, -3)

Step-by-step explanation:

x²-9=0

ax²+bx+c=0

Comparing we get,

a= 1

b= 0

c = -9

Determinant: b²-4ac

= 0² - 4(1)(-9)

= 36>0

D > 0

Therefore, the equation has real and unequal roots.

Algebraic identity:

x² - a² = (x-a)(x+a)

Using this identity

x²-9 = (x+3)(x-3)

Roots are 3 and -3 which are real and not equal to each other

Hope this answer helps you ..

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