Mathematics, 25.06.2020 05:01 hjgdk2167
Given an IVP an(x)dnydxn+an−1(x)dn−1ydxn−1+…+a1( x)dydx+a0(x)y=g(x)an(x)dnydxn+an−1( x)dn−1ydxn−1+…+a1(x)dydx+a0(x)y=g(x ) y(x0)=y0, y′(x0)=y1, ⋯, y(n−1)(x0)=yn−1y(x0)=y0, y′(x0)=y1, ⋯, y(n−1)(x0)=yn−1 If the coefficients an(x),…,a0(x)an(x),…,a0(x) and the right hand side of the equation g(x)g(x) are continuous on an interval II and if an(x)≠0an(x)≠0 on II then the IVP has a unique solution for the point x0∈Ix0∈I that exists on the whole interval II. Consider the IVP on the whole real line sin(x)d2ydx2+cos(x)dydx+sin(x)y=tan (x)sin(x)d2ydx2+cos(x)dydx+sin(x )y=tan(x) y(1)=11, y′(1)=4,y(1)=11, y′(1)=4, The Fundamental Existence Theorem for Linear Differential Equations guarantees the existence of a unique solution on the interval
Answers: 3
Mathematics, 21.06.2019 19:30
If (17, 4) is an ordered pair of the inverse of f(x), which of the following is an ordered pair of the function f(x)? a. (17,4) b. (4.17) c. (4,0) d. 0,17)
Answers: 2
Mathematics, 21.06.2019 19:30
Evaluate 3(a + b + c)squared for a = 2, b = 3, and c = 4. a. 54 b. 243 c.729 add solution .
Answers: 1
Mathematics, 21.06.2019 19:30
Finally, the arena decides to offer advertising space on the jerseys of the arena’s own amateur volley ball team. the arena wants the probability of being shortlisted to be 0.14. what is this as a percentage and a fraction? what is the probability of not being shortlisted? give your answer as a decimal. those shortlisted are entered into a final game of chance. there are six balls in a bag (2 blue balls, 2 green balls and 2 golden balls). to win, a company needs to take out two golden balls. the first ball is not replaced. what is the probability of any company winning advertising space on their volley ball team jerseys?
Answers: 3
Mathematics, 21.06.2019 20:40
The graph of a function f(x)=(x+2)(x-4). which describes all of the values for which the graph is negative and increasing? all real values of x where x< -2 all real values of x where -2
Answers: 2
Given an IVP an(x)dnydxn+an−1(x)dn−1ydxn−1+…+a1( x)dydx+a0(x)y=g(x)an(x)dnydxn+an−1( x)dn−1ydxn−1+…+...
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