A 120-gallons (gal)tank initially contains 90 lb of a salt dissolved in 90 gal of water. Brine containing 2 lb/gal of salt flows into the tank at the rate of 4gal/min. The mixture is kept uniform by stirring, and the stirred mixture flows out at the rate of 3gal/min. How much salt does the tank contain when it is full

The tank will contain 202 Ib of salt when it's full.

Step-by-step explanation

To find the amount of salt in the tank at time t= x(t)

If x(0)= 90Ib

To find the volume of the tank at time t

V(t)= 90+(4-3)t=90+t gal

Other solutions are found attached

x+y=90

x=30-y=x

step-by-step explanation:

if you understand you will get the answer

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