What can you about the value of a if the equation y=ax^2-8 has no solutions? Plz explain!

If a is negative or zero  there are no real solutions

Step-by-step explanation:

y=ax^2-8

Set equal to zero to find the solution

0 =ax^2-8

Add 8 to each side

8 = ax^2

Divide by a  a cannot be zero or we cannot divide by it

8/a = x^2

Take the square root of each side

sqrt(8/a) = sqrt(x^2)

We need 8/a to be positive for it to have real solutions

That means a has to be positive

If a is negative or zero  there are no real solutions

l.ln.lln.k.nkl

step-by-step explanation:

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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