The scatter plot shows the number of pumpkins that have been picked on the farm during the month of October: A scatter plot with points showing an upward trend with points that are moderately spread out from a line of best fit. The y axis is labeled Number of Pumpkins and the x axis is labeled Days in October Part A: Using computer software, a correlation coefficient of r = 0.51 was calculated. Based on the scatter plot, is that an accurate value for this data? Why or why not? (5 points) Part B: Instead of comparing the number of pumpkins picked and the day in October, write a scenario that would be a causal relationship for pumpkins picked on the farm. (5 points)

Answer/Step-by-step explanation:

A. Taking a look at the attached scatter plot below which is being described in the question, we can observe that the data points which are moderately spread out away from the line of best fit however show a positive correlation. The correlation coefficient would be moderate. Thus, a correlation coefficient r = 0.51 for the data cannot be far from the accurate value as this would represent a scatter plot having data points that are moderately spread out from the line of best fit. A value higher than 0.51 and closer to a value of 1 would suggest that the data points are closely clustered and not moderately spread out from the line of best fit.

B. A scenario that could be casual relationship of pumpkins picked is the number of pumpkins picked in relation to the amount of rainfall received or the number of pumpkins picked in relation to the amount of fertilizer used in kg.

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)