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Mathematics, 24.06.2020 16:01 dee3874
Four horizontal forces of magnitudes 1 N, 2 N, 3N and 4N act at a point in the direction whose bearings are 000^0, 060^0, 120 ^0and 270 ^0respectively and a 5th horizontal force of magnitude 3 N now acts at the same points so that the resultant of all five forces has a bearing of 090^0. Find the bearing of the 5th force
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Four horizontal forces of magnitudes 1 N, 2 N, 3N and 4N act at a point in the direction whose beari...
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