7. The length of a minute hand of a clock is 3.5cm. Find the angle it turns through if it sweeps an area of 48 cm. (Taken=22/7)
(3 marks)
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The angle it turns through if it  sweeps an area of 48 cm²   is   448.8°

Step-by-step explanation:

If the length of a minute hand of a clock is 3.5cm, to find the angle it turns through if it  sweeps an area of 48 cm, we will follow the steps below;

area of a sector = Ф/360  ×   πr²

where Ф is the angle,  r is the radius   π is a constant

from the question given, the length of the minute hand is 3.5 cm, this implies that radius r = 3.5

Ф =?   area  of the sector= 48 cm²    π =

we can now go ahead to substitute the values into the formula  and solve Ф

area of a sector = Ф/360  ×   πr²

48   =  Ф/360  ×   × (3.5)²

48 = Ф/360  ×   ×12.25

48 = 269.5Ф / 2520

multiply both-side of the equation by 2520

48×2520 = 269.5Ф

120960 = 269.5Ф

divide both-side of the equation by 269.5

448.8≈Ф

Ф = 448.8°

The angle it turns through if it  sweeps an area of 48 cm²   is   448.8°

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

answer: first option i.e. 'a' is correct.

step-by-step explanation:

since we have given that

number of minutes to wrap a small gift box = 4 minutes

we need to find the number of gifts to be wrapped in 5 minutes

since there is a direct variation, as the number of minutes will increase with   number of gifts to be wrapped.

so, let the number of gifts to be wrapped in 5 minutes be x.

so, it becomes,

hence, first option 'a'   is correct.