Find (fg)(x) using long division for f(x)=2x3−12x2+7x−27 g(x)=2x2+5 The quotient is The remainder is

f(x)/g(x) = x - 6 + (2x+3)/(2x^2+5)

Quotient = x - 6

Remainder = (2x+3)/(2x^2+5)

Step-by-step explanation:

Getting x-6:

What number multiplies with 2x²+5 to get 2x³+...?

that number is x, so that's your first number. You multiply it with 2x²+5 and subtract it like how you would do divison by hand back in elementary school.

Now what number multiplies with 2x²+5 to get -12x²+ ...?

that number would be 6, so that's your second number. Multiply 2x²+5 with 6 and subtract it from -12x²+ ....

Now you have 2x+3. What number multiplies with 2x²+5 to get 2x+3? That number doesnt exist so 2x+3 is your remainder.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15