At a local college, 138 of the male students are smokers and are non-smokers. Of the female students, are smokers and are non-smokers. A male student and a female student from the college are randomly selected for a survey. What is the probability that both are non-smokers?

The probability that both the male and female student are non-smokers is 0.72.

Step-by-step explanation:

The complete question is:

At a local college,178 of the male students are smokers and 712 are non-smokers. Of the female students,80 are smokers and 720 are nonsmokers. A male student and a female student from the college are randomly selected for a survey. What is the probability that both are non-smokers?

Solution:

Let, X denote the number of non-smoker male students and Y denote the number of non-smoker female students.

It is provided that:

X' = 178

X = 712

Tx = 890

Y' = 80

Y = 720

Ty = 800

Compute the probability of selecting a non-smoker male student as follows:

Compute the probability of selecting a non-smoker female student as follows:

Compute the probability that both the male and female student are non-smokers as follows:The event of any female student being a non-smoker is independent of the male students.

Thus, the probability that both the male and female student are non-smokers is 0.72.

10% of increase is the final answer! : )

the radius is 2 times the diameter.

step-by-step explanation: