Degree 3 polynomial with integer coefficients with zeros 7i and 9/5 Write it as a polynomial

Using the factor theorem, the polynomial is given by:

The Factor Theorem states that a polynomial function with roots is given by:

In which a is the leading coefficient.

In this problem:

Then, considering a leading coefficient of 1:

Multiplying by 5:

A similar problem is given at link

f(x) = 5x^3 - 9x^2 + 245x - 441.

Step-by-step explanation:

Complex zeros are in conjugate pairs so the third zero is -7i.

In factor form we have:

f(x) = (x - 7i)(x + 7i)(5x - 9)

= (x^2 - 49i)^2)(5x - 9)

= (x^2 + 49)(5x - 9)

= 5x^3 - 9x^2 + 245x - 441.

answer: -1

step-by-step explanation: