A student identification card consists of 5 digits selected from 10 possible
digits from 0 to 9. Digits cannot be
repeated. Find the probability that
randomly generated card has the
exact number 94213.

Step-by-step explanation:

Given

ID Card of 5 digits

Possibly Digits = {0,1...,9}

Required

Probability that a card has exact number 94213

First, we have o determine the total possible number of ID card numbers

Let the card number be represented by ABCDE

Given that repetition of digits is not allowed;

A can be any of 10 digits

B can any of the remaining 9 digits

C can be any of the remaining 8 digits

D can be any of the remaining 7 digits

E can be any of the remaining 6 digits

Total number of cards = 10 * 9 *8 * 7 * 6

Total = 30240

Provided that the card number is generated at random; each card number has the same probability of

Hence, the probability of having 94213 is

to find the total number of combinations, multiply the quantity of each item by each other:

2 pairs of shoes x 3 pairs of shorts = 6 different combinations.

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: