Grace invested $5,200 in an account paying an interest rate of 4.6% compounded daily. Assuming no deposits or withdrawals are made, how much money, to the nearest dollar, would be in the account after 11 years?

Step-by-step explanation:

Use this formula for when compounding is either not continuous or is not annually:

where P is the initial investment, r is the interest rate in decimal form, n is the number of times the compounding occurs per year, and t is the time in years.  For us:

P = 5200,

r = .046,

n = 365, and

t = 11

and

and

and

A(t) = 5200(1.658408042) so

A(t) = $8623.72

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00