rewrite 2x^2+2y^2-8x+10y+2=0 in standard form. Find the center and radius of the circle. Show all of your work for full credit

Radius of circle is 12.64 units and

center of circle is (8,-10).

Step-by-step explanation:

Given ,

Equation of circle is 2x^2+2y^2-8x+10y+3=0.

comparing given equation ofvcircle with the general ewuation of circle x^2+y^2+2gx+2fy+C=0 we get,

g=-8

f=10

and,c=2

Now we know,

center of circle=(-g,-f)

={-(-8),-(10)}

=(8,-10)

Again,radius of circle is given by:

r=(g^2+f^2-c^2)^1/2

={(-8)^2+(10)^2-(2)^2}^1/2

=(64+100-4)^1/2

=(160)^1/2

=root under 160

=12.64 units

[note i use root as ()^1/2 cause i couldnt fint root sign in my mobile]