An object is traveling around a circle with a radius of 5 centimeters. If in 20 seconds a central angle of 1/3 radian is swept out, what is the angular speed of the object? What is its linear speed?

step-by-step explanation:

$6.42

step-by-step explanation:

m∠a is 90°

m∠b is 40°

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen