The slope of any line perpendicular to AB, where A(0, -3) and B(4, 9) are two points on the line, is m = -3 -1/3 3 -3 -1/3 3

m = -1/3

Step-by-step explanation:

First find the slope using

m= (y2-y1)/(x2-x1)

   = (9 - -3)/(4-0)

   = (9+3)/(4-0)

   = 12/4

    = 3

We want the slope that is perpendicular  Perpendicular slopes multiply to -1

m * 3 = -1

m * 3 /3 = -1/3

m = -1/3

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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sorry i just need to anwers this to get points

step-by-step explanation: