Consider the following set of sample data. 18 26 30 42 50 52 52 76 78 84
For the given data, the mean is, the median is, and the mode is.
Suppose the value 76 in the data is mistakenly recorded as 55 instead of 76. For the sample with this error, the mean is, the median is, and the mode is. The mean, the median, and the mode. Suppose the value 76 in the original sample is inadvertently removed from the sample. For the sample with this value removed, the mean is, the median is, and the mode is. The mean, the median, and the mode.

For the given data, the mean is 50.8, the median is 51, and the mode is 52.

For the sample with this error, the mean is 48.7, the median is 51, and the mode is 52.

For the sample with this value removed, the mean is 43.2, the median is 50, and the mode is 52.

Step-by-step explanation:

We are given the following set of sample data below;

18, 26, 30, 42, 50, 52, 52, 76, 78, 84.

The formula for calculating mean is given by;

         Mean  =  

                     =    

                     =    =  50.8

For calculating median, we have to observe that the number of observations (n) in our data is even or odd, i.e;

                    Median  =  

                    Median  =  

Now, here in our data the number of observations is even, i.e. n = 10.

So, Median  =  

                    =  

                    =  

                    =    =  51

A Mode is a value that appears the maximum number of times in our data.

In our data, the value 52 is appera]ing maximum number of times, i.e. 2 times which means that mode of our data is 52.

Now, suppose the value 76 in the data is mistakenly recorded as 55 instead of 76. For the sample with this error,

            New Mean  =    

                                =    =  48.7

Now, suppose the value 76 in the original sample is inadvertently removed from the sample. For the sample with this value removed,

            New Mean  =    

                                =    =  43.2

            So, Median  =  

                                 =  

                                 =   = 50

linearly: 8560 bacteria

exponentially: approximately 75233 bacteria

step-by-step explanation:

assuming it is not exponential (we would have some really complicated logarithms), let's say it is linear. then, after 5 hours, it increased by 1200 bacteria, so every hour it increases by 240 bacteria. this means that after 19 hours, we get 19 * 240 + 4000 bacteria or 3800 + 760 + 4000 = 7800 + 760 = 8560 bacteria.

because it says round your answer, i will do this exponentially (with a calculator, of course). first, we need to find how much it multiplies by every hour, by taking the 5th root of 52/40 or 13/10. this is approximately 0.167. we still need to add 1 to this, because we are multiplying by that number, not adding that amount of the number. now, we just calculate 4000 * (1.167)^19. use a calculator to get approximately 75232.6, or 75233.