The formula for the area of a triangle is A = one-half b h. Hiro is solving the equation for h; his work is shown below. What mistake did Hiro make? A = one-half b h. 2 times A = 2 times (one-half b h). 2 A = b h. 2 A minus b = h. Hiro should have divided both sides of the equation by 2. Hiro should have divided both sides of the equation by b. Hiro should have added b to both sides of the equation. Hiro should have subtracted 2 from both sides of the equation.

Hiro should have divided both sides of the equation by b

Step-by-step explanation:

Given the formula for area of a triangle (A) = ½bh, Hiro was expected to solve for h.

To find out where Hiro made a mistake, let's solve for h step by step as it ought to be solved.

Thus,

A = ½ bh

==>Multiply both sides by 2:

2*A = 2 * [½bh]

2A = bh

==>Divide both sides by b:

(2A)/b = (bh)/b

(2A)/b = h

h = (2A)/b

The mistake Hiro made was that he subtracted b from both sides of the equation instead if dividing both sides by b.

Hiro should have divided both sides of the equation by b

The correct answer is

B) Hiro should have divided both sides of the equation by b.

I just took the quiz on edge

google dat sis

step-by-step explanation:

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x