Mathematics, 27.08.2019 18:30 khynia11
Find dy/dx given y = definite integral 1/(1+t^2) . upper cosx. lower 0. show steps/explain.
Answers: 1
![\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](/tpl/images/0203/1111/fb0e0.png)
![\displaystyle \frac{d}{dx}[\int\limits^x_a {f(t)} \, dt] = f(x)](/tpl/images/0203/1111/3819f.png)
![\displaystyle y' = \frac{d}{dx} \bigg[ \int\limits^{\cos x}_0 {\frac{1}{1 + t^2}} \, dt \bigg] \cdot \frac{d}{dx}[\cos x]](/tpl/images/0203/1111/7b15d.png)
Fundamental Theorem of Calculus 2: Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ![\displaystyle y' = \frac{1}{1 + \cos^2 x} \cdot \frac{d}{dx}[\cos x]](/tpl/images/0203/1111/9511c.png)
Trigonometric Differentiation: Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 
Simplify: Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 
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Find dy/dx given y = definite integral 1/(1+t^2) . upper cosx. lower 0. show steps/explain....
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