In an experiment to study the regulation of insulin secretion, blood samples were obtained from seven dogs before and after electrical stimulation of the vagus nerve. The following values show, for each animal, the increase (after minus before) in the immunoreactive insulin concentration (µU/ml) in pancreatic venous plasma. 30 100 60 30 130 1,060 30

For these data, Student's t method yields the following 95% confidence interval for the population mean:
-145< m <556
Is Student's t method appropriate in this case? Why or why not?

Yes, it is appropriate to use Student's t method because we don't have any information about the population standard deviation.

Step-by-step explanation:

We are given that in an experiment to study the regulation of insulin secretion, blood samples were obtained from seven dogs before and after electrical stimulation of the vagus nerve.

The following values show the increase in the immunoreactive insulin concentration (µU/ml) in pancreatic venous plasma;

30, 100, 60, 30, 130, 1,060, 30.

Also, it is given that Student's t method yields the following 95% confidence interval for the population mean:   -145< m <556.

Firstly, here it is appropriate to use Student's t method because we don't have any information about the population standard deviation.

So, the pivotal quantity for a 95% confidence interval for the population mean is given as;

                        P.Q.  =    ~

where, = sample mean increase in the immunoreactive insulin concentration =    =  205.71

            s = sample standard deviation =    = 378.72

            n = sample of dogs = 7

Also,   at = 5% with (7-1 = 6) degree of freedom is 2.447 from t-table.

So, 95% confidence interval for the population mean () is given by :

                      =  

                      =  

                      =  [205.71 - 350.27 , 205.71 + 350.27]

                      =  [-145 , 556]

Hence, 95% confidence interval for the population mean is [-145, 556].

step-by-step explanation:

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.