What is the equation of a line , in general form, that passes through points (-1,2) and (5,2)

y-2=0

Step-by-step explanation:

In y=mx+b

m=(y2-y1)/(x2-x1) [2]

Or another way of thinking about it is rise over run.

define point (-1,2) as x1,y1

define point (5,2) as x2,y2

substitute into formula [2]

m=(2-2)/(5-(-1))

We know that 2-2=0 therefore the slope (m) is 0

y=0x+b

Or simply

y=b

to solve for b we substitute into the formula any of the points

2=b for y1

or 2=b for y2

b=2

therefore y=2

to convert it into general form make the equation equal 0

y-2=0

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation: