If x = 39, y = 58, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answer to the nearest hundredth.

1.64 units

Step-by-step explanation:

Given the following :

X = 39°

Y = 58°

AC = 4 units

Using triangle ABC with x = 39° and AC = 4UNITS,

USING THE Pythagoras, the SOHCAHTOA notation:

AC = opposite = 4units

AB = hypotenus

Sinθ = opposite / hypotenus

x = Θ = 39°

Sinx = opposite / hypotenus

Sin39° = 4 / AB

0.6293203 = 4 / AB

AB = (4  ÷ 0.6293203) = 6.3560629 units

Taking triangle ADC, with x = 58° and AC = 4UNITS,

AC = opposite = 4units

AD = hypotenus

Sinθ = opposite / hypotenus

y = Θ = 58°

Sinx = opposite / hypotenus

Sin58° = 4 / AD

0.8480480 = 4 / AD

AD = (4  ÷ 0.8480480) = 4.7167136 units

Difference between AB and AD

(6.3560629 - 4.7167136)  = 1.6393493

= 1.64 units

d (5 x (-20)) * (100 x (0.7))

step-by-step explanation:

5÷1/100 * -.7 *-20

copy dot flip

5*100 * -.7 *-20

rearrange

5*-20   * 100 *-.7

-100   *-70

7000

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.