A 3 kg block is pulled with a force of 45 b along with frictionless horizontal surface at an angle of 30 degrees what is the horizontal force acting on the block

Fₐ ≈ 38.97 N

Step-by-step explanation:

The illustration forms a right angle triangle with the horizontal side been the side of horizontal force.

The horizontal component of the applied force can be calculated as follows

Force applied on the block = 45 N

The force on the horizontal is the force of acceleration use to pull the block .

Fₐ = 45 N cos 30°

The formula is gotten by using the cosine ratio of the right angle triangle formed.

Recall

cos 30° = adjacent/hypotenuse

Fₐ = 45 N cos 30°

Fₐ = 45 × cos 30°

Fₐ = 45 × 0.86602540378

Fₐ = 38.9711431703

Fₐ ≈ 38.97 N

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.