A car bought for RS 1,000,000 depreciates each year by 5%.what is the insurance premium paid in the first year , second year , and the third year of purchase? Answers soon!!

Step-by-step explanation:

Given the cost of a car to be RS 1,000,000, if the car depreciates yearly by 5%, then the insurance premium paid which is the operating expenses eacg year will be calculated as thus;

In the first year;

insurance premium paid = 5% of RS 1,000,000

= 5/100 * 1,000,000

= RS50,000

cost of the car after the first year of usage = 1,000,000-50,000

= RS 950,000

In the second year;

Insurance premium paid in the second year = 5% of RS 950,000

= 5/100 * 950,000

= 5*9,500

= RS 47,500

cost of the car at the end of second year = 950,000-47,500 = RS 902,500

In the third year;

Insurance premium paid in the third year = 5% of RS 902,500

= 5/100 * 902,500

= 5*9,025

= RS 45,125

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)