A circle is shown. 2 raddi are drawn. A chord connects the points of the radii on the circle to each other to form a triangle. The radii have lengths of 5 feet. A perpendicular bisector cuts through an angle with a measure of 72 degrees and cuts the opposite side of the triangle into 2 equals parts with measures of 2.9 feet. The length of the bisector is 4 feet. The space between the chord and the outline of the circle is shaded. What is the area of the shaded portion of the circle? (5π – 11.6) ft2 (5π – 5.8) ft2 (25π – 11.6) ft2 (25π – 5.8) ft2

Step-by-step explanation:

Given:

Length of radius of circle = 5 feets

Length of perpendicular bisector = 4 feets

To find:

Area of the shaded portion of the circle

Solution:

As OD is perpendicular bisector of AB,

Area of = 1/2 (base) × (height) =  square feets

Area of sector AOBC =  square feets

Here, r denotes radius of circle

So,

Area of shaded portion = Area of sector AOBC - Area of =  

on friday there were 15 birds

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square