A park in the shape of quadrilateral PQRS is bordered by four sidewalks. Find the measure of each exterior angle of the park.

15z=

7z=

7z=

11z=

135°, 63°, 63°, 99°

Step-by-step explanation:

Find attached the diagram used in solving the question.

We would use formula for sum of interior angles to get each exterior angle.

From the diagram, we added additional variables to be able to solve for sum of interior angles.

Sum of angle on a straight line = 180°

a° +15z° = 180°

b° +7z° = 180°

c° +7z° = 180°

d° +11z° = 180°

Where a,b,c and d are interior angles

Sum of interior angles = 180(n-2)

n = number of sides

For quadrilateral, n= 4

a°+b°+c°+d° = 180(n-2)

180-15z +180-7z+180-7z+180-11z = 180(4-2)

720-40z = 180(2)

720 - 360 = 40z

z = 360/40

z = 9

Each exterior angle:

15z = 15×9 = 135°

7z = 7×9 = 63°

7z = 7×9 = 63°

11z = 11×9 = 99°

answer: about 22.67

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )