A random sample of 1,000 couples was asked the question, "How many children presently reside in your household? Number of Children Frequency

0

225

1

112

2.

460

3

101

4

68

5 or more

34

What number of children occurred the most frequently? Calculate this percent. (2 points)

O 2.54%

2.217%

2.46%

O 5 or more, 3.4%

2, 46%

Step-by-step explanation:

==>Given:

Number of Children=>Frequency

0=>225

1=>112

2=>460

3 =>101

4=>68

5 or more=>34

Total no. of couples surveyed=>1000

==>REQUIRED:

No./% of children with the highest frequency.

==>SOLUTION:

The no. of children that occurred the most is 2, having a frequency of 460.

The % = 460 ÷ 1000 × 100

= 0.46 × 100

= 46%

Our answer is 2, 46. The number of children 2, which occurs most frequently has a percentage of 46.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right