Given that circle Q has a radius of 5 and a center of (1,4), which point lies on the perimeter of circle Q?

(x-1)^2 + (y-4)^2 = 5^2

Step-by-step explanation:

In order to find the points that lie on the perimeter of the circle, you find the  algebraic equation of the circle.

The general equation for a circle is given by:

        (1)

The last is a circle centered at the point (h,k) and with radius r.

In this case you have a circle with a radius of r = 5, and the circle is centered at (1,4). Then, you have:

h = 1

k = 4

r = 5

You replace the values of h, k and r in the equation (1):

All point that lies on the curve of the last equation, are point that lie on the perimeter of the circle

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step-by-step explanation:

answer:   y=2x-3

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