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Mathematics, 18.06.2020 18:57 LadyHolmes67

Explain what is meant by the equation lim x β†’ 8 f(x) = 9. If |x1 βˆ’ 8| < |x2 βˆ’ 8|, then |f(x1) βˆ’ 9| < |f(x2) βˆ’ 9|. The values of f(x) can be made as close to 8 as we like by taking x sufficiently close to 9. f(x) = 9 for all values of x. If |x1 βˆ’ 8| < |x2 βˆ’ 8|, then |f(x1) βˆ’ 9|≀ |f(x2) βˆ’ 9|. The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 8. Is it possible for this statement to be true and yet f(8) = 6? Explain. Yes, the graph could have a hole at (8, 9) and be defined such that f(8) = 6. Yes, the graph could have a vertical asymptote at x = 8 and be defined such that f(8) = 6. No, if f(8) = 6, then lim xβ†’8 f(x) = 6. No, if lim xβ†’8 f(x) = 9, then f(8) = 9.

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Explain what is meant by the equation lim x β†’ 8 f(x) = 9. If |x1 βˆ’ 8| < |x2 βˆ’ 8|, then |f(x1) βˆ’ 9...
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