O f(x) = x2 - 4x – 21
Mathematics, 17.06.2020 07:57 richardcarmona54
Which function has real zeros at x = 3 and x = 7?
f(x) = x2 + 4x - 21
O f(x) = x2 - 4x – 21
Of(x) = x2 – 10x + 21
O f(x) = x2 – 10x - 21
Answers: 2
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You know the right answer?
Which function has real zeros at x = 3 and x = 7?
f(x) = x2 + 4x - 21
O f(x) = x2 - 4x – 21
O f(x) = x2 - 4x – 21
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