What is the equation of the line that passes through the point (9, 6) and is perpendicular to the line y = 3x - 5?

Step-by-step explanation:

y = 3x - 5

m₁ = 3

The required line is perpendicular to y = 3x - 5. Let the required line's slope be m₂

m₂ = -1/m₁

m₂ = -1/3

Point (9,6)

Equation of line: y - y₁ = m(x - x₁)

y - 6 = (-1/3)(x - 9)

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)