Write an interval {x|-3

I will consider , otherwise it don't make sense. If I were wrong I will try to answer in the comment section.

Once will always be positive, -3 is the lowest solution.

Therefore,

Interval notarion will be

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

step-by-step explanation:

the true ones are a b and d