A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is replaced before the second marble is drawn, what is P(blue second | green first)? A.210
B.410
C.510
D.610

4/10

Step-by-step explanation:

4 blue and 6 green marbles. = 10 marbles

We draw a second marble

P(blue ) = blue marbles / total marbles = 4/10

The first is an independent even since the marble is replaced

P( blue second given a green first) = 4/10

d

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.